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9y^2+23y-32=0
a = 9; b = 23; c = -32;
Δ = b2-4ac
Δ = 232-4·9·(-32)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-41}{2*9}=\frac{-64}{18} =-3+5/9 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+41}{2*9}=\frac{18}{18} =1 $
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